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OpenStudy (anonymous):
How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?
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OpenStudy (anonymous):
Molarity = Moles/Volume of the solution. moles of NaOH = 27.5 * 0.270= 7.425 mili moles or \[7.4\times10^{-3} moles\].thanks for asking the question.
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