Question

okay question is eliminate the parameter and obtain the standard form of the rectangular equation...x=2t-3 and y=3t+3 i have what i think is the answer is it right???

Answer 1

solve for t in the first equation and substitute that into the y=3t+3... what did you get?

Answer 2

i got t=y/3-1

Answer 3

i mean what's your equation in xy after you eliminated the parameter t...

Answer 4

im not sure wat ur trying to ask:(

Answer 5

those are parametric equations of x and y.... the question asks to eliminate the parameter t so that your equation is only in terms of x and y... no "t"...

Answer 6

o. okay then i guess i am not sure how to carry out this problem then...thats my problem

Answer 7

let \[t = \frac{(x +3)}{2} \]

substitute it into y

\[y = \frac{3(x +3)}{2} + 3\]

simplifying

\[y = \frac{3x}{2} + \frac{9}{2} + 3\]

\[y = \frac{3x}{2} + \frac{15}{2}\]

Answer 8

The whole deal is linear. Let t=0 to get a point (x_0,y_0). Then let t=1 to get (x_1,y_1). Those two points will allow you to get the equation of a line in the Cartesian plane.

Answer 9

okay can i ask what EXACTLY does eliminating the parameter mean?

Answer 10

nice one^^^ ... that's another way....:)

Answer 11

or imply?

Answer 12

it means to get rid of the t in both equations... this can only be done by rewriting one equation so that t is the subject.

when this is done, substitute into the other equation to get the equation of your line

Answer 13

okay wat do i substitute?... sorry :(

Answer 14

anyone?

Answer 15

:(

Answer 16

help?

Answer 17

ok... if x = 2t - 3

can you make t the subject of the equation..?

Answer 18

yeah. i think. u mean like let it be t=? right or am wrong?

Answer 19

thats what you want... what will t be equal to..?

Answer 20

t will be = to y/3-1.....?

Answer 21

no lets work on x = 2t - 3

Answer 22

o. okay sorry it'll be x/2+3/2

Answer 23

yeap or without the expansion

\[t =\frac{ (x +3)}{2}\]

now substitute it into

\[y = 3t + 3\]

this will give an equation with 2 unknowns... x and y

Answer 24

okay let me plug it in

Answer 25

wait so the equation i have t=x/2+3/2 that is eliminating the parameter? or is it wen i get the 2 unknowns?

Answer 26

a little care with the algebra expansion

its \[y = 3 \times \frac{x +3}{2} + 3\]

Answer 27

wait where did u plug in t=x/2+3/2 just now?

Answer 28

I have write it as

\[\frac{x + 3}{2} = \frac{x}{2} + \frac{3}{2}\]

Answer 29

and remember its 3*x and 3* 3

Answer 30

okay but y are they = to each other is wat i dont understand