Question

if the poly. x^4-6x*+16x^2-25x+10 is divided by another poly. x^2-2x+k,the remainder comes out to be x+a,find k and a.

Answer 1

what is '-6x*' is??

Answer 2

* stands for cube

Answer 3

well i think. if (x^2-2x+k)*(x+a)
the highest power of its ans would be x^3
how could it have a x^4 ?

Answer 4

http://openstudy.com/study#/updates/4fd3195ae4b057e7d22204f5

Answer 5

@apoorvk

Answer 6

@AndrewNJ - that "x+a" is the remainder, not the quotient.

Answer 7

ya..i miss it
let me try to solve it

Answer 8

the remainder is x+a
so we can multiply (dx^2+ex+f) to simply satisfy the power of two, three and four
(x^2-2x+k)(dx^2+ex+f)=dx^4-2dx^3+dkx^2+ex^3-2ex^2+ekx+fx^2-2fx+fk=dx^4+(e-2d)x^3+(dk-2e+f)x^2+(ek-2f)x+fk
contrast to x^4-6x^3+16x^2-25x+10
so we can have
d=1
(e-2d)=-6
(dk-2e+f)=16
(ek-2f)=-25-1=-26
fk=10-a
try to solve d,e,f,k,a so,
d=1
e=-4
f=3
k=5
a=-5

Answer 9

thxxxxxxxxxxxxxxxxxxxxx

Answer 10

:)

Answer 11

i wish it has no mistake

Answer 12

u r osum dude

Answer 13

Isn't there a better way to do it?

Answer 14

I hate it when I get too many constants.

Answer 15

ya.. i dont have a better one
it seems have to satisfy every coefficient of each power,it need hard work

Answer 16

dis is correct

Answer 17

the method is no prob
but im afraid it has calculus error

Answer 18

id gonna sleep. see u tomorrow, if it exists some problems :)