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Physics 15 Online
OpenStudy (anonymous):

the value of surface density on a conducting plate is -2 x 10^-6 C/m^2 . A 100eV electron moving towards the plate jut fails to strike it then the distance between the initial position of electron from the plate will be ??

OpenStudy (anonymous):

@vanihba ? @ANKITOM

OpenStudy (ujjwal):

\[E=\frac{\sigma}{\varepsilon _0} \]\[E=\frac{V}{r}\] Equalize both. you will get r. Here V is 100 V Ans: 4.427*10^-4 m

OpenStudy (anonymous):

@ujjwal will u plz show me ur calculation i used the same formula but unable to get the answer...

OpenStudy (experimentx):

whats your answer??

OpenStudy (anonymous):

its a long calculation i left it.. :(

OpenStudy (experimentx):

@ujjwal 's method seems valid

OpenStudy (anonymous):

actaully guys i m stuck in this question by the statement "plate just fails to strike it then the distance between the initial position of electron from the plate will be " i mean what they are trying to tell us can u guys show me the figure and ye @experimentX ujj wals method is valid and i used the same way but unable to get answer :(

OpenStudy (ujjwal):

that is not a long calculation. you have values of \(\sigma\) , \(\varepsilon _0 \) and V. just substitute values to get r in the equation \[\frac{\sigma}{\varepsilon_0}=\frac{V}{r}\]

OpenStudy (anonymous):

yea i got it :P i dunno wat i m doing dat time have one more doubt hold on posting it and thnx for everyone :)

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