Question

Help Me Please!!! with factoring special products....
x^6-y^6

Answer 1

This is a difference in squares pattern, regardless of the higher powers.
(x^6 - y^6) = (x^3 + y^3)(x^3 - y^3)
Then, this is a sum and difference in cubes.
\[(x^{3} + y^{3}) = (x + y)(x^{2} - xy + y^{2}\]
\[(x^{3} - y^{3}) = (x - y)(x^{2} + xy + y^{2}\]
(x^3 + y^3)(x^3 - y^3)
(x + y)(x^2 - xy + y^2)(x - y)(x^2 + xy + y^2)

Answer 2

Do you understand?
\[(x + y)(x - y)(x^{2} - xy + y^{2})(x^{2} + xy + y^{2})\]

Answer 3

Thank You! But I am a little confused on how you got this....

(x3+y3)=(x+y)(x2−xy+y2) at the beginning

Answer 4

Well, are you in algebra I or Algebra II?

Answer 5

Algebra 2

Answer 6

Well, this is a pattern that most algebra II classes teach. It's just something that most people have to memorize in Algebra II. Maybe your class didn't teach it?

Answer 7

It's kind of like difference is squares, you memorize the patterns :)

Answer 8

I'm understanding it now. Thanks so Much!

Answer 9

Anytime :)