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Physics 16 Online
OpenStudy (anonymous):

In a cinema, a picture 2.5 cm wide on the film is projected to an image 3.0 m wide on a screen which is 18 m away. The focal length of the lens is about:

OpenStudy (anonymous):

The magnification is m = hi/ho and hi/ho = di/do. This can be solved for the distance to the image, and then the lens equation 1/do+1/di=1/f. Thus the focal length is 15 cm http://hep.physics.lsa.umich.edu/p240/exams/exam3.html

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

Make sense?

OpenStudy (anonymous):

hmmm actually no isnt the equation 1/f=(1/i)+(1/p)

OpenStudy (anonymous):

Go Here and look at problem number 4 it will help you: http://web.ics.purdue.edu/~jensend/media/pdf/phys241/exams/exam03/Fall2006.pdf

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

my image = 19.6...is that right? and object = 1.6 but then it =1.47...?

OpenStudy (anonymous):

if i convert to cm then its 147cm...somthing is wrong...

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