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a(t)=p*e^rt how may years will it take for 50 dollar investment to grow to 1000 dollars compounded continuosly at a rate of 5%
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so you have \[1000 = 50e^{0.05t}\] solve for t \[20 = e^{0.05t}\] take the base e log of both sides \[\ln (20) = 0.05t\] \[t = \frac{\ln(20)}{0.05}\] t = 59.9146 years
@campbell_st so where did the 20 come from
20 = 1000/50
@campbell_st oohhh thank you
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