Question

Find the area under the standard normal distribution curve between z = –2.05 and z = 2.05.

Answer 1

\[
\int_{-2.05}^{2.05}
\frac{e^{-\frac{x^2}{2}}}{\sqrt
{2 \pi }} \, dx=0.959636
\]

You can also find it from a z-table.

Answer 2

thank you

Answer 3

From the tables you get
P[ Z< 2.05]= .9798
P[ -2.05 < Z < 2.05]= 2P[ Z< 2.05]-1 = 2(.9798)-1=.9596