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Mathematics 8 Online
OpenStudy (anonymous):

The shaded area in the diagram below shows the cross section of a pyramid intersected by a plane that passes through the apex and is perpendicular to the base. The base of the pyramid is a square of side 22 cm. Each edge of the triangular faces is 15 cm long. Which is the best approximation of the perimeter of the cross section?

OpenStudy (anonymous):

31 cm 35 cm 42 cm 52 cm

jimthompson5910 (jim_thompson5910):

you're missing the diagram

OpenStudy (anonymous):

OpenStudy (anonymous):

:)

jimthompson5910 (jim_thompson5910):

thanks

jimthompson5910 (jim_thompson5910):

The base of that shaded triangle is 22 cm since it's parallel to that length, can you see this?

OpenStudy (anonymous):

yes each side of the base is 22 cm right

jimthompson5910 (jim_thompson5910):

you got it

jimthompson5910 (jim_thompson5910):

The slant height of the pyramid is all we need now. So let's find it. Let's use the Pythagorean theorem to do that. a^2 + b^2 = c^2 11^2 + b^2 = 15^2 121 + b^2 = 225 b^2 = 225-121 b^2 = 104 b = sqrt(104) So the exact length of the slant height is sqrt(104) So the perimeter of this shaded triangle is P = sqrt(104)+sqrt(104)+22 P = 10.198039+10.198039+22 P = 42.396078 Which rounds to 42 cm So it's choice C

OpenStudy (anonymous):

Thank you so much, I had no Idea where to go with it!

jimthompson5910 (jim_thompson5910):

I'm glad I could help

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