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Simplify. 1/2-i plz help!
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so its .5-i. i dont think you cant simplify that unless you want to do (1/2)-(sqrt(-1))
Multiply numerator and denominator by the conjugate of 2-i which is 2+i
\[\frac{1}{2-i}*\frac{2+i}{2+i}\] \[\frac{2+i}{2+1}\] \[\frac{2+i}{3}\] \[\frac{2}{3}+\frac{1}{3}i\]
\[(2-i)(2+i)\] \[4+2i-2i-i^2\] \[i^2=-1\] \[4-(-1)\] \[4+1=5\]
Sorry \[\frac{2}{5}+\frac{1}{5}i\]
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Or is the question: \[\frac{1}{2}-i\] ?
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