Question

Solve: x(squared) + 4x+8=0

Answer 1

\(x^2+4x+8=0\)
\[x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]

Answer 2

First factor the equation, if possible.

Answer 3

salam22 its a quadratic equation so you want me to make a grafh of it or only zeros?

Answer 4

If not then you the quadratic equation given by @Mimi_x3

Answer 5

And in this case b^2-4ac<0 So you will have 2 complex zero's.

Answer 6

Yeah, looks like a complex.

Answer 7

So just plug in the values a=1, b=4 and c=8. and remember that you should have 2 complex zero's

Answer 8

The answer choices I have are:
A) 2+2i, 2 - 2i
B) -2 + 4i, -2 - 4i
C) -2+2i, -2 - 2i
D) 2+4i, 2-4i
Can someone tell me how to do the questions as well as what the answer is?

Answer 9

Sorry. Actually, I have the answers already. I
just don't know how to do the problem.

Answer 10

That's okay :). Don't be afraid to let us know.

Answer 11

So,\[x=\frac{-4 \pm \sqrt{(-4)^2-4(1)(8)}}{2*1}\]

Answer 12

Can you clean that up @salam22

Answer 13

getting my graphing calculator so I know how to do it. 1 min. please.

Answer 14

\[x=\frac{-4 \pm \sqrt{16-32}}{2}\]
\[x=\frac{-4 \pm \sqrt{16-32}}{2}\]
\[x=\frac{-4 \pm \sqrt{-16}}{2}\]
\[x=\frac{-4 \pm \sqrt{16}\sqrt{-1}}{2}\]
\[\sqrt{-1}=i\]
So,
\[x=\frac{-4 \pm 4*i}{2}\]
\[x=\frac{-4}{2} \pm \frac{4}{2}i\]

Answer 15

What course is this for? Are you allowed to use a graphing calculator?

Answer 16

And then am sure you can simplify your solution? You are familiar with complex number right?

Answer 17

about to log off and log back in using another computer, so my mom can continue using this 1. I have a study guide which my teacher provided the answers, but we're expected to find out how to do the problems. I have a total of 85 questions, and I only need help with 18 of them so I can prepare for my final on Thursday. I'm trying to get the 18 done 2night so I can bring it to my teacher 2morrow. So any help is VERY appreciated. Wish I found this site earlier, cuz i was just about to go to bed, now I have to stay up :-(

Answer 18

So the answer would be c

Answer 19

Algebra 2 and yes, calculators are allowed now and during the test

Answer 20

Oh, I understand... well try using WolframAlpha to see it that also helps because sometimes people take long to reply.

Answer 21

Well, All the best! Did you understand what I did?

Answer 22

THANKS SO MUCH! U R THE BOMB!

Answer 23

Yes, I understand exactly what you did.

Answer 24

You're surely welcome and...Aww, thanks!

Answer 25

and btw, I'm not familiar with complex numbers

Answer 26

Im writing down the answer u provided so I can practice on my own. Will post the next question shortly.

Answer 27

Oh... yikes... Well, remember how they once said you can't take the square root of a negative number? When raised to an even power. Well you actually can and mathematicians decided to call this set of numbers complex numbers \[i=\sqrt{-1}, i^2=-1, i^3=-i, i^4=1\] and they pretty much repeat the pattern after i^4 started back at i

Answer 28

And unfortunately I have to go to bed now... but if you post it quickly I can help you with it if I am able to :).

Answer 29

ok Thank you.
solve by completeing the square 8x^2 - 80x = 32. can you help me work this out

Answer 30

To complete the square you must have the coefficient of the x=1 to 1 so first divide by 8

Answer 31

I accidently closed this question and started a new one since its a new example. Sorry. Are u still able to reply to this post?

Answer 32

Okay I will look for it