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OpenStudy (anonymous):
x^4-25^2+144=0
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sam (.sam.):
x^4-25^2+144=0
u=x^2
u^2-25u+144=0
(u-9)(u-16)=0
u=9 u=16
x^2=9 x^2=16
solve
OpenStudy (theviper):
\[x^4-25x^2+144=0\] is this ur equation??
OpenStudy (anonymous):
oh the 25^2 is supposed to be 25x^2.....sorry.
OpenStudy (anonymous):
Don't forget to substitute back for u
OpenStudy (anonymous):
yes @TheViper
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OpenStudy (theviper):
\[x^4-9x^2-16x^2+144\]
OpenStudy (theviper):
\[x^2(x^2-9)-16(x^2-9)\]
OpenStudy (theviper):
\[=>(x^2-16)(x^2-9)\]
OpenStudy (theviper):
That's ur ans.:)
OpenStudy (anonymous):
those aren't my numbers?........or was that an example of the same?
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OpenStudy (theviper):
What do u want to say??
OpenStudy (anonymous):
the numbers you replied with aren't the same from the question..
OpenStudy (theviper):
No ans should be this
do u know the ans if yes than reply it plz:)
OpenStudy (anonymous):
@TheViper You can further factor that sinc eit says factor completely
OpenStudy (anonymous):
There are 2 difference in squares there.
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OpenStudy (anonymous):
Actually, @.Sam. has done most for you..
x^4-25x^2+144=0
(x^2-9)(x^2-16)=0
(x^2-9)=0 or (x^2-16)=0
x^2 = 9 or x^2 =16
\(x=\pm 3\) or \(x=\pm4\)
OpenStudy (theviper):
Oh I factor that eq.
u want to solve for x
OpenStudy (anonymous):
Thanks @RolyPoly @Calcmathlete @TheViper@.Sam.
OpenStudy (theviper):
U r welcome @teun7840
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