Question

Please help

Express \(36x^2 - 252\) as a difference of two squares

the answer is supposed to have some binomials..idk

Answer 1

\( \color{Black}{\Rightarrow (6x + \sqrt{252})(6x - \sqrt{252}) }\)

Simplify sqrt252 further and you're done. Can you do it now?

Answer 2

252 is not a perfect square sadly ;) sorry

Answer 3

Hint: the squares are binomials

Answer 4

I know but do you know how to simplify radicals?

Answer 5

252 = 15.87

Answer 6

and it's your last day so live it because we'll have a verification system

Answer 7

if you don't know the answer get out of the post ;)

Answer 8

\[x=\sqrt{7}\]
i think so.

Answer 9

no i dont think so..the answer has some binomials

Answer 10

@ParthKohli What do you mean by "it's your last day so live it because we'll have a verification system"? Just curious.

Answer 11

it's a threat lol

Answer 12

Alright, did you get your answer for this question yet though?

Answer 13

no

Answer 14

Well, do you remember how to simplify radicals such as √252?

Answer 15

\[\sqrt{252} = \sqrt{9 * 4 * 7} = 3 * 2\sqrt{7} = 6\sqrt{7}\]? Does this look familiar?

Answer 16

Well, you just plug that into what ParthKohli did.
(6x + 6√7)(6x - 6√7)

Answer 17

@mr.awesome Do yuo get it?

Answer 18

actually the answer is the diffence of two squares of binomials..that's what i dont get

Answer 19

ParthKohli has the correct answer mr.awesome, it is the difference of two squares of binomials...i noticed that many students are misled when teachers in the classroom make it seem as though you can only have difference of two squares when the TERM A& Term B of
(TERM A) ^2 -(TERM B)^2 are whole numbers and perfect squares i.e. x^2-1, B=1 is a whole number and a perfect square and x^2-1=(x+1)(x-1)
but then later on you run into situations when term A& B aren't whole numbers and you still have (TERM A) ^2 - (TERM B)^2= (TERM A + TERMB)(TERMA-TERMB)
take for instance 37x^2-11= ( sqrt(37)x+ sqrt(11)) (sqrt(37)x-sqrt(11))