integrate (tan(x)+1)/(tan(x)-1)..help me solve this please..
hmm wait..it seems it'swritten \[\frac{\tan x + 1}{\tan x - 1}\] sorry misread
how to integrate that??
\[\large\int\limits\frac{\frac{sinx}{cosx}+1}{\frac{sinx}{cosx}-1} dx \] Weierstrass substitution might work..
try multiplying by conjugate (what it is called??) of denominator and ... change into double angle
wont weisestrass substitution work? http://en.wikipedia.org/wiki/Weierstrass_substitution
if i take u is tan(x)+1 it won't work
indeed it wont work. try manipulating it with trig identities; changding tanx = sinx/cosx like i suggested.
ok i will try..thanks :)
this should yield to something like \[ \frac{1 + \sin 2x}{-\cos 2x} \]
is that by using trigonometry identities?
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