a baseball pitcher throws a baseball with a speed of 41m/s. Estimate the average acceleration of the ball during the throwing motion. In throwing the baseball, the pitcher accelerates the ball through a displacement of 3.5m... I worked it out but my answer is wrong and I don't know why..
it is 240.14m/s^2 isn't it?
yes but how? you are like a physics genius..can i borrow your brain for my exam?
lol, you make me blush! You see, the pitcher has accelerated the ball from rest to 41m/s in a distance of 3.5m So, using
v=u+at -(1) s=(v+u)1/2t -(2) So ans: 240.1428ms^-2
\[v _{f}^{2}=v _{0}^{2}+2as\] calculate 'a'
@Mif.100 how did you find the time?
@rajathsbhat and then after that i can calculate time with v=vo x at?
yes.
@rajathsbhat didn't you leave out the displacement part? v^2=vi^2+2a(x-xi)
in v=u+at
s=displacement
oo okay, thank you! :) i have two more questions.. will post them soon! x
welcm
looking forward to it :)
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