Solve. Round results to the nearest thousandth. 2x2 + 3x - 7 = 0

Question

Solve. Round results to the nearest thousandth.  2x2 + 3x - 7 = 0

anonymous · Answer

-1000

campbell_st · Answer

you need the general quadratic formula. 

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

in your question a = 2, b = 3 and c = -7

then 

$$x = \frac{-3 \pm \sqrt{3^2 - 4 \times2\times(-7)}}{2\times2}$$

$$x = \frac{-3 \pm \sqrt{67}}{4}$$

you need to evaluate 

$$x = \frac{-3 + \sqrt{67}}{4}...and... x= \frac{-3 - \sqrt{67}}{4}$$ correct to 3 decimal places.

anonymous · Answer

but it is not quadratic

campbell_st · Answer

$$2x^2 + 3x - 7 = 0$$

seems to be a quadratic to me...

anonymous · Answer

its 2 multiplied by 2

anonymous · Answer

if it is $$2x^{2}$$ it has to be 2x^2

shubhamsrg · Answer

if you're using that much common sense @izanagi.wielder ,,tell me this,,why would anyone give the ques as 2*x*2 instead of 4x ?? makes sense?

anonymous · Answer

its a book copied question

anonymous · Answer

well it will be better to the questioner

anonymous · Answer

:D