Question

Find the area:

Answer 1

Find the area of the part of the surface \[z=x+y ^{2}\] that lies above the triangle with vertices (0,0), (1,1), (0,1).

Answer 2

@A.Avinash_Goutham @apoorvk @AndrewNJ @bmp @wasiqss @lgbasallote please try

Answer 3

@CliffSedge

Answer 4

wat is density correction :/

Answer 5

ok wait ill attach a file and the solution is the solution to question 2, so yu have to go down.... i dont understand the solution

Answer 6

Have you tried graphing it to get an idea of what it looks like? That sometimes help to develop a solution.

Answer 7

ive tried alot of things, i was hoping dere would be an easier way to do it other dan the way it is done in da solutions, cos i dont understand the solutions

Answer 8

its part 2 of the solutions

Answer 9

wat's ur reference book?

Answer 10

its a pelletty one called Thomas' Calculus

Answer 11

naah it's a good book.......i used the same book............ :P

Answer 12

:/ reallllyyyyy?????? i have it with me, ill check in dat

Answer 13

@CliffSedge did u get that?

Answer 14

Yeah, I see in the solution guide, it recommends using horizontal strips and that seems pretty obvious given the orientation of the surface to the base triangle.
It's not so obvious how to get the double integral, though.