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Convert the complex number 3 + 3i into its polar representation.
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A. 2 sqrt3 (cos(60) + isin(60)) B. sqrt3 (cos(225) + isin(225)) C. 3(cos(135) + isin(135)) D. 3 sqrt2 (cos(45) + isin(45))
I think it is A but I am not sure
For a complex number a+bi the magnitude is found by sqrt(a^2 +b^2) the angle is found by tan(theta) = b/a |z|-->Magnitude θ-->angle z=|z|(cos(θ)+isin(θ))
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Yes thank you very much, it was D.
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