Question

A detective finds a murder victim in a room with constant temperature 21◦C. At 5:00am, the body’s temperature was 34.2◦C. One hour later, it was 31.2◦C. Normal body temperature is 37◦C. Assume the body’s temperature, B(t), follows Newton’s Law of Cooling.

(a) Set up and solve the differential equation for B(t).
(b)what time did the murder occur
ANSWERS
a)
y = 16e^((ln(10.2/16) - ln(13.2/16))x)+21
and the solution I have gotten was

b)
34.2 =16e^-((ln(10.2/16) - ln(13.2/16))x)+21
=
-0.746
or
approximately 4:15pm

Answer 1

can someone check this for me?

Answer 2

yeah sounds right