Question

Two identical charged particles of mass m=1.5 kg and electric charge Q=-4.8 μC are placed on an frictionless 39° incline. One of them falls down to the bottom and stops against the wall. The other stays at rest in the middle of the incline as shown in Figure. Find is the distance between the particles.

Answer 1

For the particle at rest, all forces must cancel out since it is static. The gravitational force points down, the normal force is normal to the surface, and the electric force points away from the other charge with magnitude given by Coulomb's Law.\[F_E = \frac{1}{4\pi \epsilon_0} \frac{Q^2}{r^2}\]Here, \(r\) is the separation between the charges.

Answer 2

i keep getting an incorrect answer :/

Answer 3

is the answer not 0.152 m?

Answer 4

can you draw the figure?