Question

(x3 - 18x2 +95x - 126) ÷ (x -9)

Answer 1

Long division - do u know how to do it?

Answer 2

\[
x^3-18 x^2+95 x-126=(x-9) (x-7)
(x-2)
\]

Answer 3

no

Answer 4

okay, here's a site to show you: http://www.purplemath.com/modules/polydiv2.htm
i would draw it out but i'm on a laptop right now so my hannswriting is barely legible.

Answer 5

*handwriting

Answer 6

\[
\frac{x^3-18 x^2+95
x-126}{x-9}=\frac{(x-9) (x-7)
(x-2)}{x-9}=(x-7) (x-2)
\]
but, I suggest that you do it with using long division.

Answer 7

is it x^2 + 9x + 14 or x^2 - 9x + 14

Answer 8

yes, because that factors to (x-7)(x-2), good job!

Answer 9

wait which one

Answer 10

the second one

Answer 11

Here how you factor the numerator:

\[
x^3 - 18 x^2 + 95 x - 126=\\
x( x^2 - 18 x + 95) -126=\\
x( x^2 -18x + 81 -81 +95) -126=\\
x( x^2-9) + 14 x -126 =\\
x( x-9)^2 + 14 (x -9) =\\
(x-9)(x^2 -9x +14)= \\
(x-9)(x-7)(x-2)

\]

Answer 12

@eliassaab nice method, i'll try it sometime (: