how can you tell if a systems of equations has no solution?
They lines never intersect.
They never meet. In other words, their slope is same but y-intercepts are different.
A system of equations will have no solution if you run into a contradiction. For example, if you have one equation telling you that y=x+1, and another telling you that y=x-1, they can't both be true. It's a contradiction, so there must be no solution.
convert the system into an augmented matrix,if the ranks are not equal you won't get solution to the given system.
What? If you convert it into an augmented matrix, that matrix will have a rank. Each equation won't have its own rank. And if you're looking for the condition for there not being a solution, you're looking for a row of zeros with a non-zero term in the augmented portion of the matrix. Which, coincidentally, is the same as my suggestion of looking for a contradiction.
let Ax=b is the system of equations in the matrix form. augmented matrix is A|b, if rank(A)≠rank(A|b) this system of equations have no solutuon.
Okay, I see what you mean. The rank of the matrix is different from the rank of the augmented matrix. The way that you initially phrased that was really unclear.
i'm really sorry about that
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