Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

how can you tell if a systems of equations has no solution?

OpenStudy (saifoo.khan):

They lines never intersect.

OpenStudy (saifoo.khan):

They never meet. In other words, their slope is same but y-intercepts are different.

OpenStudy (anonymous):

A system of equations will have no solution if you run into a contradiction. For example, if you have one equation telling you that y=x+1, and another telling you that y=x-1, they can't both be true. It's a contradiction, so there must be no solution.

OpenStudy (anonymous):

convert the system into an augmented matrix,if the ranks are not equal you won't get solution to the given system.

OpenStudy (anonymous):

What? If you convert it into an augmented matrix, that matrix will have a rank. Each equation won't have its own rank. And if you're looking for the condition for there not being a solution, you're looking for a row of zeros with a non-zero term in the augmented portion of the matrix. Which, coincidentally, is the same as my suggestion of looking for a contradiction.

OpenStudy (anonymous):

let Ax=b is the system of equations in the matrix form. augmented matrix is A|b, if rank(A)≠rank(A|b) this system of equations have no solutuon.

OpenStudy (anonymous):

Okay, I see what you mean. The rank of the matrix is different from the rank of the augmented matrix. The way that you initially phrased that was really unclear.

OpenStudy (anonymous):

i'm really sorry about that

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!