Question

Simplify
x^2-36/ x^2+3x -18

Answer 1

\[x^2-36/ x^2+3x -18\]
Multiply by \[(x^2/x^2)\] (which is the same thing as 1)
to get:
\[(x^4+3x^3-18x^2-36)/(x^2)\]

Answer 2

Hint: Think of the method for GCD (Greatest Common Denominator) ;-)

Answer 3

i dont get it :"(

Answer 4

did you understand mine?

Answer 5

agentx5 must misunderstood it

Answer 6

whats the over all answer though

Answer 7

What two things can be cancel ??

Answer 8

x+6?

Answer 9

so its -6/-3?

Answer 10

is should be (x-6)/(x-3)

Answer 11

sorry i left the x's out. and THANKS! Deff one of the most helpful people

Answer 12

did you understand how i factor out the equations from the original problem?

Answer 13

ehh not really. what hapened with the -18

Answer 14

Helpful tip: parenthesis are very important! ^_^

Answer 15

Additional helpful tip:
1. Click the "∑ Equation" button below
2. Type "frac {numerator}{denominator}" (but no quotes, logically, and replace the words with your equation or expression's numerator or denominator)
3. Insert & tada! Looks like this:

\[\frac {numerator}{denominator}\]

Answer 16

\[x^2−36/x^2+3x−18 \neq \frac{x^2−36}{x^2+3x−18}=\frac{(x−6)(x+6)}{(x−3)(x+6)}=\frac{x−6}{x−3}\]

What I wrote was correct based on what I saw, @OsmundF
\[x^2−36/x^2+3x−18\]
\[(\frac{x^2}{1}−\frac{36}{x^2}+\frac{3x}{1}−\frac{18}{1} ) , GCD = x^2\]
\[\frac{(x^2*x^2+3 x*x^2-18 *x^2-36*(x^2/x^2))}{x^2}\]
\[\frac{(x^4+3 x^3-18 x^2-36)}{x^2}\]

^_^

(and depending on which problem you intended, @Haleybob, now you have answers for each one and processes on how to repeat for similar problems!)

Answer 17

Oh and to answer your follow question, the -18 = (-3) * (+6). In reverse, take -18 / +6 and see what you get. :-)