Question

sqrt{9x+67}=x+5

Answer 1

Is this the question?
\[\sqrt{9x+67}=x+5\]

Answer 2

Square both sides of the equation
\[(\sqrt{9x+67})^2=(x+5)^2\]

Answer 3

Square both sides & solve it:)

Answer 4

The squares cancel
\[9x+67=x^2+10x+25\]
Move all terms to one side and cancel
\[0=x^2+10x-9x+25-67\]

Answer 5

Are you able to take it from there @pinkwhispers80?

Answer 6

\[0 =x^2+x-42 \]
\[(x+7)(x-6)=0\]
According to the zero factor theorem either x=6 or x=-7