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How many atoms are in 65 grams of argon?
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n= m/M n=N/L where: m - mass M - molar mass N - number of atoms/molecules L - avogadro constant so: N= m*L/M
can you help me through it please?
well i have written it all now all you need to do is to put in numbers
i honestly have no clue how to even start the problem
N= 65 g * 6,022 * 10^23 mol-1 / 39,9 g mol-1
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is it 9.79x10^23?
yes i think it is...
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