Find the slope-intercept (y = mx + b) form of the line satisfying the given conditions. Parallel to y = -2x, passing through (0,1)
In order for the line to be parallel to y=-2x, it must have the same slope. The point (0,1) happens to be the y-intercept. So from this information, we know m and b. The equation of the line is\[y=-2x+1\]
y-y1=m(x-x1) m=0, y1=1 and x1=0 y-1=-2(x-0) y-1=-2x Slope-intercept form is y=mx+c y=-2x+1
ummmm i dont get it iam sorry
Are you familiar with the equation \[m=\frac{y_2-y_1}{x_2-x_1}\]
And this is the same thing as \[y_2-y_1=m(x_2-x_1)\]
And like @SBurchette was saying earlier parallel lines have the same slope. So the slope of a line parallel to y=-2x is -2 because m here is -2.
i was working with that a little last week
And it's okay if you don't understand but what exactly is it that you don't understand?
Did you figure it out @compaqangel0205 if you want to start over we can do so in another question :)
i was saying its all hard but it would not post ty
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