@some1 Indicate in standard form the equation of the line passing through the given points. L(5, 0), M(0, 5)
okai so do the same thing. x2-x1/y2-y1 5-0/0-5=-1 slope=-1. pick a pair of coordinates, and substitute -1 in for m in y=mx+b y=mx+b 0=-1(5)+b 5=b. y=-x+5. =)
but..the answer has to start with x_________
ok then it's x+y=5. Just move the x to the other side. Sorry it's standard form -.- Heh. Ma bad. xD
:D
how about this one Indicate in standard form the equation of the line passing through the given points. X(0, 6), Y(5, 6) if it starts with y________
okai. same thing, shell. x2-x1/y2-y1 0-5/6-6 slope=.......uhhhhhhh. undefined...let's just say 0 for now. xD. y=mx+b 6=0(6)+b 6=b. y=6. no that can't be right....o_O
lol im telling u...its so hard:/
it's not hard it's just...confoosing. lemme do dis again.
:/ k
ok so the slope formula is the other way around xD whoops. but that doesn't change the answer considering we used 0 anyway.....
ughh darn!!:c
hm. For the first time. I don't know an algebra question. fml. I had this all down easily. Something's wrong with the problem!!!!! :O
:c WHYYYYYYY!!
Yea it's definitely the problem. i just graphed and everything. lol. did you try to put in y=6? does it work?
it doesnt!!!:c
Did you copy the problem right into this website? o_O
Indicate in standard form the equation of the line passing through the given points. X(0, 6), Y(5, 6) Place the symbols on the grid to complete the equation. y___________________
y=6 :D
u sure?
It can't be jolly. The two points share a common coordinate, 6. When a pair share a common coordinate, the equation must be y= or x= that coordinate. lol.
yea it's y=6. I said that before a;lsdkfj;alskdjf;lasfd
i ment the x-y=1 for the first question asked. .. might be wrong
omg :c this is soo hard!!!!!!!!! :c
and this one? Indicate the equation of the given line in standard form. The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(-2, -2), C(1, -1), and D(6, 4).
what about that question?
how do you solve it?
you on the same lesson?
yeah.
what question is it?
this one: Indicate the equation of the given line in standard form. The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(-2, -2), C(1, -1), and D(6, 4). xDDD
lol i ment.. what numer @jolly
lol :P
@some1 you do AOA too? i'm on 16 section 2
lol i have no idea buddy. But list problems and i'll solve em for ya. :P
we're not on the same lesson then.. cause 16 is this one for me ->Indicate the equation of the given line in standard form. The line through (2, -1) and parallel to a line with slope of
woops. i meant #22.
ohhhhh:)
hey @some1 for this question: Indicate the equation of the given line in standard form. The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(-2, -2), C(1, -1), and D(6, 4). is it x=y? or did i do it wrong?
i know BD is the longer diagonal
6+2/4+2 8/6 would be slope. check your double negatives. they become positive. like in english, shell! :D
:D awesome!
so 4/3 simplified, and y+2 = 4/3(x+2)?
yah.
y = 4x +6 is what i got ..
if u simplify that's what u should get =D
k, thanks :)
Join our real-time social learning platform and learn together with your friends!