Find a number Z so that P{ N(4, 4) < Z } = .75 ( the probability that a normal 4, 4 is less than Z equals .75) can you show steps to see how you did it thanks
is your notation N(\(\mu,\sigma^2\)) or N(\(\mu,\sigma\))
2nd one
so the mean is 4 and the standard deviation is 4
yes
your notation for the problem is not very nice...I'm going to modify it a little and you tell me if it is kn to you Let \(X\) have a normal distribution with mean 4 and standard deviation 4 you wint to find the value of \(x\) such that \[P(X\le x)=.75\]
*want to find...
um i dont even know how to start it
are you ok with how I worded the problem?
so the z score is .7734
yes
where do you get that?
I see what you did...no that is not correct
you need to go backwards from what you just did
what do you mean backwards
\[P(X\le x)=.75\] \[\Rightarrow P\left(\frac{X-4}{4}\le \frac{x-4}{4}\right)=.75\] \[\Rightarrow P\left(Z\le \frac{x-4}{4}\right)=.75\] \[\Rightarrow P\left(Z\le z\right)=.75\] looking up on a table (or a good calculator) one should get z=.6745
my calculator says it is z=.67448974945
but \[z=\frac{x-4}{4}\] solve for x gives \[x=4z+4\] plugging in the value of z from above and we get \[x=6.6979589978\]
how do you figure the z cause when i look for 0.75 i get o.7734
you are looking it up wrong...the .75 is a probability ...look in the middle of the table for a number that is closest to .75
oh that makes sense now k thanks
good
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