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Mathematics 13 Online
OpenStudy (anonymous):

Find X,Y, & Z in the image...

OpenStudy (anonymous):

OpenStudy (maheshmeghwal9):

Use sine ratio as; \[\color{red}{\sin 60^o=\frac{z}{15}.} and \color{blue}{\sin 30^o=\frac{x}{15}.}\]

OpenStudy (maheshmeghwal9):

gt it?

OpenStudy (maheshmeghwal9):

And for "y" u take one of inner right angled triangles & use the suitable trigonometrical ratio as above to get the answer^_^

OpenStudy (anonymous):

sooo Z=12.990 and X=7.5 ?

OpenStudy (maheshmeghwal9):

yeah well done:)

OpenStudy (maheshmeghwal9):

& also do for "y" now:)

OpenStudy (anonymous):

what would it be as a fraction though?

OpenStudy (anonymous):

yeah

OpenStudy (maheshmeghwal9):

\[z=\frac{15\sqrt{3}}{2}. \] & \[x=\frac{15}{2}.\]

OpenStudy (anonymous):

okay is Y the same as Z?

OpenStudy (maheshmeghwal9):

NO; in the inner right angled triangle of right side u see; That \[\color{green}{\sin 30^o=\frac{y}{z}.}\] So, \[\color{purple}{y=\frac{z}{2}.}\]It means "y" is half of "z". i.e.; \[\color{red}{y=6.49}\]

OpenStudy (maheshmeghwal9):

I think u must have gt it now:)

OpenStudy (anonymous):

I do :D but can u put in fraction form for me please. and I also need help finding "a" and "b"

OpenStudy (maheshmeghwal9):

ya; \[y=\frac{12.990}{2}.\] & for 'a' & 'b'; I m thinking^_^

OpenStudy (maheshmeghwal9):

ya, i gt it As u have found x, y, & z so now u should be able to find a & b by trigonometrical ratio in inner right angled triangles. But I will not do this. U have to do it on ur own.

OpenStudy (maheshmeghwal9):

u can do so best of luck^_^

OpenStudy (anonymous):

is "a" 25.98/2 ?

OpenStudy (maheshmeghwal9):

one minute!

OpenStudy (maheshmeghwal9):

no

OpenStudy (maheshmeghwal9):

try more Hint: - use cosine ratio:)

OpenStudy (anonymous):

is "a" 7.5 ?

OpenStudy (maheshmeghwal9):

no; \[\color{red}{\cos 60^o=\frac{1}{2}=\frac{a}{x}}\] so \[\color{purple}{a=\frac{x}{2}.}\] Now, find "b" on ur own:) but plz do it carefully now^_^

OpenStudy (maheshmeghwal9):

k! so\[\color{red}{\cos 30^o=\frac{b}{z}=\frac{\sqrt{3}}{2}}\]

OpenStudy (maheshmeghwal9):

so\[b=\frac{z \sqrt{3}}{2}.\]

OpenStudy (maheshmeghwal9):

now calculate:)

OpenStudy (anonymous):

i got 12.990

OpenStudy (maheshmeghwal9):

whose value? a or b?

OpenStudy (anonymous):

b

OpenStudy (maheshmeghwal9):

LOL how can that be? z=12.990 & b is z's sqrt{3}/2 part I mean\[b=\frac{z \sqrt{3}}{2}=\frac{12.990\times 1.73}{2}.\]

OpenStudy (maheshmeghwal9):

u see above ur answer. I have written solution:)

OpenStudy (anonymous):

so its 11.236 ?

OpenStudy (maheshmeghwal9):

one minute:)

OpenStudy (maheshmeghwal9):

yeah definitely:) well done^_^ So u gt all x, y, z, a, b.

OpenStudy (anonymous):

lol thankyou, how do u put a and b in fraction form though?

OpenStudy (maheshmeghwal9):

lol they are written above already. but by the way\[a=\frac{7.5}{2}.\] & \[b=\frac{22.46}{2}.\]

OpenStudy (anonymous):

THANK YOU SO MUCH! ahah and thanks for your patience!

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