Question

Simplify?
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Answer 1

factorise

Answer 2

that's easy

Answer 3

u shud be able to do it

Answer 4

:$ i suck at math

Answer 5

u keep posting this way intead of trying them.......u l remain the same........

Answer 6

i post on here cause its the only way i can get help

Answer 7

well how wud u try solving this problem?

Answer 8

i really dont know, im reading the lesson again & its literally like another language to me . .

Answer 9

fine see the numerator.........wat form is it in?

Answer 10

\[\frac{n^2+8+16}{n^2-6n+9}\div\frac{n+4}{n-3}\]
\[=\frac{n^2+8+16}{n^2-6n+9}\times\frac{n-3}{n+4}\]
\[=\frac{(n+4)^2}{(n-3)^2}\times\frac{n-3}{n+4}\]
\[=\]

Answer 11

now cancel factors that appear in both numerator and the denominator