Question

If (x+a) is a factor of 2Xsquare(two X square)+2ax+5x+10,find a ?
guys i need the procedure;

Answer 1

\[\large 2x^2 + 2ax + 5x + 10\] that's the polynomial right?

Answer 2

2?

Answer 3

@gadivamsi is there an = 0? or that's really just the question??

Answer 4

ya lgbasallote,it is 2x2+2ax+5x+10

Answer 5

but is there an = 0?

Answer 6

u kno that's an expression....nd it's got a factor

Answer 7

no

Answer 8

hmm im gonna assume that there's = 0 there...

well if x+a is a factor that means x = -a is a solution

if x = -a is a solution then i can substitute -a into every x

\[2(-a)^2 + 2a(-a) + 5a + 10 = 0\]
\[2a^2 - 2a^2 + 5a + 10 = 0\]
\[5a + 10 = 0\]
\[5a = -10\]

you can solve for a easily now...

Answer 9

im just thinking how you can solve for a \(\textbf{IF}\) there's no = 0

Answer 10

expression's dont have =0's u kno............wen they have a factor say x+a.......then.............f(-a) wud be 0 :|

Answer 11

what you did is right but the answer should be +2 not -2

Answer 12

GREAT! im right then!

Answer 13

it's 2

Answer 14

\[5a = -10\] divide both sides by 5
\[a = -2\]

Answer 15

hmm i knew this
but the answer in 2

Answer 16

u kno it's 5 * -a

Answer 17

ohh yeag

Answer 18

yeah*

Answer 19

i overlooked that lol \[-5a = -10\] divide both sides by -5 \[a = 2\] lol there you go

Answer 20

so i guess there was an implicit = 0 there