Question

HELP PLEASEEE! (: http://mathway.com/math_image.aspx?p=SMB02RSMB03(2(x-SMB02RSMB035SMB02rSMB03))SMB02rSMB03?p=94?p=22

Answer 1

What do we do with that?

Answer 2

I actually can't see it when I go to the link it direct me somewhere else.. Which option am I suppose to click basic math? pre-algebra?

Answer 3

All I see is \[\sqrt{(2(x-\sqrt{5}))}\]

Answer 4

@Limitless you simplify it. @purplec16 Algebra

Answer 5

what does "simplify" mean in this case?

Answer 6

What do they mean by simplify? There is not a whole lot you can do. The only outright intelligent thing you can do is remove the outermost parentheses. From there, it's purely aesthetic opinion.

Basically, \(\sqrt{(2(x-\sqrt{5}))}=\sqrt{2(x-\sqrt{5})}\).

Answer 7

:D

Answer 8

you could "distribute" and write
\[\sqrt{2x-2\times \sqrt{5}}\] but in no sense is that any "simpler" than the first expression

Answer 9

I find \(\sqrt{2(x-\sqrt{5})}\) to be the most pleasing to the eye.

Answer 10

Well, technically, \(\sqrt{2\left(x-\sqrt{5}\right)}\). :P

Answer 11

here is my brief rant
"simplify" does not have a mathematical meaning.
it usually is written as an instruction by a lazy math teacher who really means "write what i want"

there is such a thing as "simplest radical form" and also "canonical forms" but these are rarely defined

Answer 12

That's not in my answer choices though, i'll give ithem to you.
A) 2xsqr2
B) 10sqr2x
C) sqr2x-sqr10
D) xsqr2-sqr10

Answer 13

..None of those are right...

Answer 14

I agree with you, @satellite73. I believe it's basically where math becomes more like music: What looks best to you may not look the best to others.

Answer 15

One of them has to be right, it's a test and those are my only choices :(

Answer 16

Tests are not infallible nor from the mouth of Euler. There is clearly an error.

Answer 17

Do you think maybe you have to solve the answers to get the answer to the problem?

Answer 18

This is my test.

Answer 19

:D

Answer 20

Lordie, your website rendered it wrong.

Answer 21

@Limitless what does that mean?

Answer 22

Use the distributive property.

Answer 23

It means that the URL you posted has an incorrect version of the problem.

Answer 24

Ohhh. But now you see what my problems are? lol

Answer 25

Yes. To solve the first one, use the distributive property.

Answer 26

I would need help doing that also.. I'm horrible at this stuff :/

Answer 27

It's the last option.

Answer 28

Mutliply each term by sqrt{2}

Answer 29

Okay. The distributive property means, for anything \(a\), \(b\), and \(c\), you have that \(a(b+c)\) is the same as \(ab+ac\). So you multiply what's outside the parentheses by what is inside the parentheses.

Answer 30

So it would be D.

Answer 31

Correct. You understand why it is D now, right?

Answer 32

I have an idea. What about the second equation?

Answer 33

You do the same thing.

Answer 34

But this problem is more difficult than the last one.

Answer 35

Do you know how to work with square roots when they are multiplied together?

Answer 36

No

Answer 37

Well, you just use this fact \(\sqrt{a}\sqrt{b}=\sqrt{ab}\) to simplify question 2.

Answer 38

This is confusing me. Multiply square root by square root to get the square root combined?

Answer 39

Yes. So when you distribute, you have \(\sqrt{6}7\sqrt{3}=7\sqrt{3\cdot 6}\). Can you think of a way to simplify that?

Answer 40

The only thing I can think of is 7sqr18?

Answer 41

Well. What's 18? It's 9 times 2. So you can simplify. \(7\sqrt{18}=7\sqrt{3^2\cdot 2}=7\cdot 3 \sqrt{2}=21\sqrt{2}\).

Answer 42

So the answer would be B?

Answer 43

Yep.

Answer 44

Thank you SO much ((:

Answer 45

You are welcome. It is good that you had such patience.

Answer 46

Do you mind helping me with my next few problems, except this time I'm dividing them?

Answer 47

I don't mind at all.

Answer 48

I tried a couple on my own, can you check to see if their right?

Answer 49

You are close on the first one. It is actually \(\frac{2\sqrt{2}}{3}\). This is because \(\sqrt{8}=\sqrt{2^2\cdot 2}=2\sqrt{2}\). You're also close on the second one. I think you just forgot the \(3\) cancels. You have: \(\frac{3}{\sqrt{3}}=\frac{3\sqrt{3}}{\sqrt{3}\sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}\)

Do you feel you understand these concepts more clearly now?

Answer 50

Ehh, not really. I barely knew what I was doing, I just gave it a shot. Lol, but I did another one on my own then I gave up.

Answer 51

You may want to practice, then. There are many worksheets online for algebra and quite a few tutorials. But the most important thing is that you have the drive to give it a try. :)

Answer 52

Lol I guess I just need a good tutor. But I posted the other one I tried up there ^^

Answer 53

It's the same one.

Answer 54

Oh, hold on.

Answer 55

Hm. How do you justify your answer?

Answer 56

I think I got it, It should be D, right?

Answer 57

Which one?

Answer 58

Question 4? Yeah, it should be. Good job. :)

Answer 59

Yay :D I solved them all except the last two.

Answer 60

These stumped me -___-

Answer 61

For the first one, ask yourself, "What's the square root of 25?" You basically have to use the fact that \(\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\). For the second one, it's easier than it looks. It simplifies to a single number. Just use what you've learned already.

Answer 62

I don't know how to do the first one, but the second one simplifies to 4/8 and that simplifies to 1/2. But I don't get how to explain ?

Answer 63

Just explain the steps you used in words. That's all. :) Tell the person grading how they could get the answer, basically.

Answer 64

How would you do the first problem, that one is different than the previous ones I did.

Answer 65

Basically, you separate the square root:
\[2\sqrt{\frac{3}{25}}=2\frac{\sqrt{3}}{\sqrt{25}}=2\frac{\sqrt{3}}{5}\]

Answer 66

So it would be answer choice B?

Answer 67

Yuppers.

Answer 68

In the last one I just put that it simplifies to 4/8 and that simplifies further to 1/2. Is that all or am I missing anything?

Answer 69

You could add that you multiplied the top and bottom of the fraction by \(\sqrt{8}\). But, otherwise, yeah. It's not that big of a question--it's more about what the person grading wants. Some people are pickier than others.

Answer 70

That means I submitted the wrong answer -.-

Answer 71

No, Aly, there are multiple answers here.

Answer 72

You can get to the answer in different ways and use different words to explain it.

Answer 73

ok, the answer is 1/2 so you did it correctly. These radicals things are too tricky!

Answer 74

Yay :DD Now I'm off to graphing systems of inequalities :/

Answer 75

Ah, yeah. Those are lame. :P