Question

Using the law of cosines, Find c.
Triangle ABC, a=8, b=6, y=60

Answer 1

what is y?

Answer 2

an angle?

Answer 3

is angle y opposite side c?

Answer 4

\(c=a^2+b^2-2ab\cos(C)\) is how this is usually written. my guess is that you have \[c^2=8^2+6^2-2\times 8\times 6\cos(60)\]

Answer 5

the triangle actually does not show where y is

Answer 6

since \(\cos(60)=\frac{1}{2}\) you get
\[c^2=8^2+8^2-8\times 6\] to calculate

Answer 7

sorry i meant
\[c^2=8^2+6^2-6\times 8\]

Answer 8

80?

Answer 9

if you are supposed to use the law of cosines, this is the only thing it can be

Answer 10

i get \(c^2=52\) making \(c=\sqrt{52}\)

Answer 11

52

Answer 12

ok, thanks!

Answer 13

or \(c=2\sqrt{13}\) if you prefer