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i have log (base x+5) 0.0001= -3 i got x=15 is this correct?
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\[\log_{x+5}(.0001)=-3 \]
is this how it is written?
yes :)
ok
ke (x+5) to the right side
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in that case.. (x+5)^-3 = 0.001
isnt it?
x+5 = 10
x=5
0.0001 = (x+5)^-3 \[\sqrt[-3]{0.0001} = x+5\]
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so it would be x=5?
yes
understand it>
yes in detail better :)
u want more detail?
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what?
did u get it?
i mean to say \[\sqrt[-3]{0.0001}\neq 1\] then how can you just say x=5 ??? O_o
its a typo its actually 0.001
ok
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it is a typo sorry!
\[\sqrt[-3]{0.001} = -0.1\]
=10
but x=5 was a choice is that not correct his math seemed correct.
there is not x=10
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x+5=10 so x=5
no debate
so if i have log sub 9 27 what would that be 3/2 correct?
yes
because 9^(3/2) = 27
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