Question

Solve the following system of equations.

2x + 3y – z = 1
3x + y + 2z = 12
x + 2y – 3z = –5

Answer 1

(3, –1, 2)
(–3, 1, 2)
(3, 1, –2)
(3, 1, 2)
Here are the answers.. I suck at Systems of Equations. :/

Answer 2

The answer choices, lol. Not the answers.

Answer 3

Use row reduction on the corresponding augmented matrix.
\[
\left[\begin{array}{ccc|c}
2 & 3 & -1 & 1 \\ 3 & 1 & 2 & 12 \\ 1 & 2 & -3 & -5
\end{array}\right]
\]In other words, swap rows, multiply rows by constants, and subtract one row from another as you please until you have an identity matrix on the left.

Answer 4

I don't understand.