Question

Can anyone set me a p=1 sphere bying using cylinderical corrdinates in integral.

Answer 1

p = 1?? what is that??

Answer 2

yeah same thing i wanna ask... what is p?

Answer 3

rho=1

Answer 4

what do you want to evaluate??

Answer 5

sorry . the volume.

Answer 6

looks like it's done here
http://www.physicsforums.com/showthread.php?t=304505

Answer 7

should it be this?

Answer 8

\[\int\limits^{2\pi}_{0}\int\limits^{1}_{0}\int\limits^{\sqrt{1^2-r^2}}_{\sqrt{1^2-r^2}} rdz dr d\theta\]

Answer 9

Hm ... i haven't tried yet, it will be good exercise for me

Answer 10

u want to convert spherical coordinate into cylindrical coordinate?

Answer 11

the upper and lower limit shouldn't be same

Answer 12

yes @kr7210

Answer 13

\[\int\limits\limits^{2\pi}_{0}\int\limits\limits^{1}_{0}\int\limits\limits^{\sqrt{1^2-r^2}}_{-\sqrt{1^2-r^2}} rdz dr d\theta\]lower s

Answer 14

then first convert into cartesian coordinate thn go for cylindrical .....

Answer 15

in this case r=rho

Answer 16

r=rho=1