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Mathematics 9 Online
OpenStudy (anonymous):

HELP THIS IS DUE IN A WHILE HELP ME PLEASE ......... Given A = {x | x < 1}, B = {x | x ≥ 5}, and C = {x | x = 5}, match the following items. 1. A U B 1. Ø 2. A U C 2. {x | x < 1 or x = 5} 3. B U C 3. {x | x < 1 or x ≥ 5} 4. A ∩ B 4. {x | x ≥ 5} 5. B ∩ C 5. {x | x = 5}

OpenStudy (anonymous):

i need help D:

OpenStudy (anonymous):

do you know what A U B means?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

or for that matter, A \(\large \cap \) B ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

you must at least have an idea, what does your notes say?

OpenStudy (anonymous):

the notes i have i got from odyssey and they dont help the give me vocab and examples

OpenStudy (anonymous):

ok... i'll explain them...:)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

A \(\large \cup \) B means the union of A and B. It mean put whatever is in set A and whatever is in set B combined. A \(\large \cap \) B means the intersection of A and B. It means what do set A and set B have in common.

OpenStudy (anonymous):

so A U B is the combined set of A and B... which matches that?

OpenStudy (anonymous):

btw... when you combine two sets, they are joined by "OR"

OpenStudy (anonymous):

ok so like A U B is {x | x < 1 or x ≥ 5} because they are combined

OpenStudy (anonymous):

yes...:)

OpenStudy (anonymous):

now let's do the second one...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

that one looks easy... A U C matches which one on the right?

OpenStudy (anonymous):

{x | x < 1 or x = 5}

OpenStudy (anonymous):

correct.... see? not too hard eh?

OpenStudy (anonymous):

what about the third one? looks like something missing between the B and C...

OpenStudy (anonymous):

its a U

OpenStudy (anonymous):

B U C

OpenStudy (anonymous):

ok so if you combine B and C what do you get?

OpenStudy (anonymous):

notice B already has what C has... so if you were to combine those two sets....

OpenStudy (anonymous):

i dont think you can combine them..........or can you

OpenStudy (anonymous):

you can always combine sets.... all things in B combined with all things in C....

OpenStudy (anonymous):

take a guess.... you only have three options...

OpenStudy (anonymous):

{x | x = 5}

OpenStudy (anonymous):

so you're saying if I combine all things in B and all things in C, i will get a set that contain only 1 thing (x=5)?

OpenStudy (anonymous):

i think i should get more than just 1 element....

OpenStudy (anonymous):

im still a little confused i dont understand how those two can be combined

OpenStudy (anonymous):

set B contains all numbers greater than 5, including 5. set C contains only 1 element, x=5 notice set B actually contains set C... we call C is a subset of B. so if I combine set B with set C, i still get everything in set B...

OpenStudy (anonymous):

os you'll just get {x | x ≥ 5} ?

OpenStudy (anonymous):

yes...:)

OpenStudy (anonymous):

wow that was easy

OpenStudy (anonymous):

yes but that's not the best part... intersection is much easier....

OpenStudy (anonymous):

A \(\large \cap \) B means what do these two have in common?

OpenStudy (anonymous):

this things <> ?

OpenStudy (anonymous):

set A contains numbers less than 1 set B contains numbers greater than 5, including 5 what do they have in common? is anything in set A in set B? and vice versa?

OpenStudy (anonymous):

yes ?

OpenStudy (anonymous):

set A = {1/2, 0, -1, -.333, -4, -500000, ....} - these are numbers less than 1 set B = {5, 5.1, 5.9, 25, 500000, ....} - these are numbers bigger than 5 including 5 can you give me a number that is in setA which is also in setB ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

no... they don't have anything in common... so the answer is the empty set. that's the zero with the slash through it.

OpenStudy (anonymous):

oh ok :)

OpenStudy (anonymous):

the last one is trivial since we did everything.... but I'd like you to see that to answer B \(\large \cap \) C, you look for the common thing(s) in set B and set C.....

OpenStudy (anonymous):

the only thing they have in common is what is in set C... x=5....

OpenStudy (anonymous):

just 5

OpenStudy (anonymous):

yep...

OpenStudy (anonymous):

good work man....:)

OpenStudy (anonymous):

thank you :)

OpenStudy (anonymous):

yw...:)

OpenStudy (anonymous):

wait i got one last question

OpenStudy (anonymous):

its diff i think from this question

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