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OpenStudy (anonymous):
|dw:1339625670134:dw|
OpenStudy (anonymous):
thats what you would solve:)
jimthompson5910 (jim_thompson5910):
Can you factor 108?
OpenStudy (anonymous):
... i think so... 6√3??
OpenStudy (anonymous):
108
Pull all perfect square roots out from under the radical. In this case, remove
the 6 because it is a perfect square.
6 3
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jimthompson5910 (jim_thompson5910):
good, \[\Large \sqrt{108}=6\sqrt{3}\]
OpenStudy (anonymous):
6√3
jimthompson5910 (jim_thompson5910):
now simplify \[\Large \sqrt{8}\]
OpenStudy (anonymous):
2√2
jimthompson5910 (jim_thompson5910):
good, so \[\Large 3\sqrt{8} = 3*2\sqrt{2} = 6\sqrt{2}\]
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jimthompson5910 (jim_thompson5910):
what about the last one
jimthompson5910 (jim_thompson5910):
\[\sqrt{27}\]
OpenStudy (anonymous):
3√3
jimthompson5910 (jim_thompson5910):
perfect
jimthompson5910 (jim_thompson5910):
Now combine like terms
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OpenStudy (anonymous):
so how would the answer look??
jimthompson5910 (jim_thompson5910):
We go from
\[\Large \sqrt{108}-3\sqrt{8}-\sqrt{27}\]
to
\[\Large 6\sqrt{3}-6\sqrt{2}-3\sqrt{3}\]
Now let x = sqrt(3) and y = sqrt(2) to get
6x - 6y - 3x
From here, combine like terms. What do you get?
OpenStudy (anonymous):
9x-6y??
jimthompson5910 (jim_thompson5910):
6x - 3x is???
OpenStudy (anonymous):
oh 3x!!!! i didnt see the- hhaha silly me!:P so thats the answer??
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jimthompson5910 (jim_thompson5910):
not yet
so
6x - 6y - 3x
becomes
3x - 6y
Now replace x with sqrt(3) and y with sqrt(2) (remember we made these assignments above)
to get
\[\Large 3\sqrt{3}-6\sqrt{2}\]