Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

PLLEEEZZ HELP!! solve:

OpenStudy (anonymous):

|dw:1339625670134:dw|

OpenStudy (anonymous):

thats what you would solve:)

jimthompson5910 (jim_thompson5910):

Can you factor 108?

OpenStudy (anonymous):

... i think so... 6√3??

OpenStudy (anonymous):

108 Pull all perfect square roots out from under the radical. In this case, remove the 6 because it is a perfect square. 6 3

jimthompson5910 (jim_thompson5910):

good, \[\Large \sqrt{108}=6\sqrt{3}\]

OpenStudy (anonymous):

6√3

jimthompson5910 (jim_thompson5910):

now simplify \[\Large \sqrt{8}\]

OpenStudy (anonymous):

2√2

jimthompson5910 (jim_thompson5910):

good, so \[\Large 3\sqrt{8} = 3*2\sqrt{2} = 6\sqrt{2}\]

jimthompson5910 (jim_thompson5910):

what about the last one

jimthompson5910 (jim_thompson5910):

\[\sqrt{27}\]

OpenStudy (anonymous):

3√3

jimthompson5910 (jim_thompson5910):

perfect

jimthompson5910 (jim_thompson5910):

Now combine like terms

OpenStudy (anonymous):

so how would the answer look??

jimthompson5910 (jim_thompson5910):

We go from \[\Large \sqrt{108}-3\sqrt{8}-\sqrt{27}\] to \[\Large 6\sqrt{3}-6\sqrt{2}-3\sqrt{3}\] Now let x = sqrt(3) and y = sqrt(2) to get 6x - 6y - 3x From here, combine like terms. What do you get?

OpenStudy (anonymous):

9x-6y??

jimthompson5910 (jim_thompson5910):

6x - 3x is???

OpenStudy (anonymous):

oh 3x!!!! i didnt see the- hhaha silly me!:P so thats the answer??

jimthompson5910 (jim_thompson5910):

not yet so 6x - 6y - 3x becomes 3x - 6y Now replace x with sqrt(3) and y with sqrt(2) (remember we made these assignments above) to get \[\Large 3\sqrt{3}-6\sqrt{2}\]

OpenStudy (anonymous):

oh ok! then that is the answer???? haha

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

hahha ok thanks a million!! <3

jimthompson5910 (jim_thompson5910):

you're welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!