If I know the lengths of two sides of a right triangle, how do I find the third? Please provide a step by step teaching example for me :)
\[a^2+b^2=c^2\]
where a and b are the sides and c is the hypotenuse
a and b are perpendicular sides.
Okay, if you know the legs of the triangle, then use the Pythagorean Theorem. a^2 + b^2 = c^2 So you put in the values of a and b (the legs) and once you get c^2, you take the square root to find the hypotenuse. Now, if you have one leg and the hypotenuse, you can still use this theorem. a^2 + b^2 = c^2 You plug in the values of a/b (doesn't matter) and c in this case, and then you can find the length of the other leg.
You need to use the Pythagorus Theorem (as stated by Romero). You can learn more about this here: http://www.mathsisfun.com/pythagoras.html
Examples: Two sides of a right triangle are given: 30 and 40. Find the hypotenuse. Plug in the values. 30^2 + 40^2 = c^2 900+1600 = c^2 2500 = c^2 c = 50 So the hypotenuse's length is 50. Another problem with the other case: If one of the legs of a right triangle is 50 and the hypotenuse's length is 130, what is the length of the other leg? Plug it in. 50^2 + b^2 = 130^2 2500 + b^2 = 16900 b^2 = 14400 b = 120 So the other leg of the right triangle is 120. Do you understand now?
THANK YOU SO MUCH EVERYONE :) I have another question though!
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