Use a graphing utility to confirm your result. Then eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve.
x=3-2t
y=2+3t
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OpenStudy (anonymous):
how is it a curve? its just a linear line isn't it. heres the graph
OpenStudy (anonymous):
i did that originally and my teacher said it was wrong. he said to eliminate the parameters. how do i do that?!
OpenStudy (anonymous):
you make the x equation equal t then sub that into the y equation then simply it
OpenStudy (anonymous):
so y = 3x - 5 i think
OpenStudy (anonymous):
sorry 2y = 3x - 5
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OpenStudy (anonymous):
so would it be t = (3-x)/2
y = (13-3x)/2
OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
i am getting \(t=\frac{3-x}{2}\) and so \(y=2+3(\frac{3-x}{2})=\frac{13}{2}-\frac{3}{2}x\)
OpenStudy (anonymous):
y = (3/2)x ?
OpenStudy (anonymous):
SO what about these equations?
x=sqrt(t)
y=1-t
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OpenStudy (anonymous):
x^2 = t
y = 1 - x^2
OpenStudy (anonymous):
and yeah @satellite73 is correct with the first one. I forgot the minus in the x equation