Question

http://www.nysedregents.org/IntegratedAlgebra/20100618exam.pdf number 35

Answer 1

do you have a graphing calculator?

Answer 2

yes

Answer 3

then you type in "abs(x)" for y1 (assuming you have a TI 83 or TI 84)

Answer 4

and "abs((1/2)x)" for y2 to graph the two equations

Answer 5

do i just plot the points they give me when i click 2nd graph

Answer 6

yes, you can do that, hitting 2nd graph gives you the table which gives you the list of points used

Answer 7

okay thank you! can you help me with another question please

Answer 8

sure thing, what's your other question?

Answer 9

http://www.nysedregents.org/IntegratedAlgebra/611/20110616-ia-exam.pdf number 36

Answer 10

Use the following formula:

Surface area = 2*(Length*Width + Length*Height + Width*Height)

or

SA = 2*(LW + LH + WH)

Answer 11

In this case, the length is x+3, so L = x+3

The width is x-4, so W = x-4

The height is 5, so H = 5

Answer 12

So

SA = 2*(LW + LH + WH)

becomes

SA = 2*((x+3)(x-4) + (x+3)*5 + (x-4)*5)

Answer 13

Do you know how to simplify that?

Answer 14

i got 2(x+3)(x+4) + 2(5)(x-4)+ 2(x+3)(5)

Answer 15

good

Answer 16

what's next

Answer 17

isnt that different from what you got

Answer 18

it's the same,you just rearranged terms and distributed

Answer 19

but that's all perfectly valid

Answer 20

then i got 2(x^2-4x+3x-12) but i dont know to distribute the other ones because when i looked at the answer it wasnt the same

Answer 21

You expanded (x+3)(x+4) to get x^2-4x+3x-12 ?

Answer 22

yes

Answer 23

well you're close, but your signs are off

Answer 24

(x+3)(x+4) should be x^2+4x+3x+12

Answer 25

how is it positive 4

Answer 26

multiply the outer terms x and 4 to get 4x

Answer 27

but its negative 4

Answer 28

no, positive x times positive 4 is positive 4x

Answer 29

SA = 2*((x+3)(x-4) + (x+3)*5 + (x-4)*5)

Answer 30

oooh right, I copied (x+3)(x+4) for some reason lol my bad

Answer 31

(x+3)(x-4) is x^2-4x+3x-12

Answer 32

okay but i dont know how to distribute 2(5)(x-4) + 2(x+3)(5)

Answer 33

2(5)(x-4)

10(x-4)

10x-40

Answer 34

and

2(x+3)(5)

2(5)(x+3)

10(x+3)

10x+30

Answer 35

but why do you multiply 2*5 and not x+3

Answer 36

I multiply 2 and 5 because you can think of 2(x+3)(5) as 2y*5 or 2*5y where y = x+3

Answer 37

afterwards, I distributed

Answer 38

i still dont get why the answer isnt 10(2x+6)

Answer 39

well you distributed the 2 through, so 2(x+3) became (2x+6)


So 2(x+3)*5 becomes (2x+6)*5


Then you can distribute the 5 through to get 10x+30

Answer 40

ok i dont get it what ever

Answer 41

thankyou

Answer 42

just keep practicing and you will eventually