Question

What is true about the solutions of a quadratic equation when the radicand in the quadratic formula is negative?

No real solutions
Two identical rational solutions
Two different rational solutions
Two irrational solutions

Answer 1

Hint!!! \[b^2 - 4ac > 0 \longleftarrow \text{2 real solutions}\]
\[b^2 - 4ac = 0 \longleftarrow \text{1 real solution}\]
\[b^2 - 4ac < 0 \longleftarrow \text{no real solution}\]

Answer 2

which do you think answers your question? :)

Answer 3

two different rational solutions

Answer 4

when something is > 0 that means that something is positive

when it's = 0 that means it's 0

when it's < 0 that means it's negative

Answer 5

again...which answers your question? /:)

Answer 6

Two irrational solutions

Answer 7

look at the question again...it's asking what if \(b^2 - 4ac\) is negative...which of the ones did i write represent the negative?

Answer 8

b2−4ac<0

Answer 9

and what did i write about that?

Answer 10

no real solution

Answer 11

thks

Answer 12

there you go