How do I solve this?

The ratio of the areas of two similar polygons is 49:16. If the perimeter of the first polygon is 22 cm, what is the perimeter of the second polygon?

Question

How do I solve this?

The ratio of the areas of two similar polygons is 49:16. If the perimeter of the first polygon is 22 cm, what is the perimeter of the second polygon?

anonymous · Answer

If these are regular polygons, then the question involves some manipulation of the equation: $$Area = (s^{2}*N)/(4 \tan (180/N))$$ where s = the length of a side, and N = the number of sides. 
Since we're assuming the polygon is regular, the perimeter can be represented by the following equation:
p = sN.
Set up a ratio of areas (e.g Area1/ Area2 = 49/16) and the denominators cancel. You're left with $$Area_1/Area_2 = ( p^2_1N )(p^2_2N)$$. 
The "N"s cancel, and you get an equation relating area and perimeter for *regular* polygons. I hope you can take it from there.