Question

A ball is dropped vertically from a height 'd' above the ground and bounces up vertically to a height 'd/2'. Neglecting subsequent motion & air resistance its velocity 'v' varies with the height 'h' above the ground as: -

Answer 1

Plz choose the correct graph & give reason of choosing to:)

Answer 2

to=> too*.

Answer 3

@ajprincess plz help:)

Answer 4

Before hitting the ground ,the velocity v is given by v2=2gd Which is a quadratic equation and hence parabolic path. Downward direction means negative velocity , After collison ,the velocity becomes positive and velocity decreases Further v12=2g(d/2)=gd Therefore v=v1√2 As the direction is reversed and speed is decreased, Hence (a) is the answer

Answer 5

is it clear?

Answer 6

one minute:)
I was outside for a while.
sorry.

Answer 7

it's k.:)

Answer 8

yea u have given right answer. & u mean
I understood that; but how it can be

Answer 9

??????????

Answer 10

jst a moment.

Answer 11

k!

Answer 12

i have problem in this