Is this a Exponential Growth or Exponential Decay, y = 0.65(1.3)^(x)
exponent positive or negative ?
its just x so im guessing positive
as you increase x, what happens to y ?
it should decrease rite
depends entirely on whether the base (in this case 1.3) is greater than or less than one
since \(1.3>1\) this models growth
so is y=1 or x=1
@satellite73 put x = 1 & x = -1 , compare the values, and tell me if it you still say it doesnt depend on exponent sign :)
?
\[ y(x) = 0.65(1.3)^{x}\] \[ y(1) = 0.65(1.3)^{1}=0.845\]\[ y(10) = 0.65(1.3)^{10}\approx8.96\] as x has grown, y has grown
you lost me entirely \(y=P_0\times b^x\) grows so long as \(b>1\) and decreases if \(b<1\)
in other word, in this example, if \[x_1<x_2\implies .65(1.3)^{x_1}<.65(1.3)^{x_2}\]
here is a nice picture showing it going up http://www.wolframalpha.com/input/?i=y+%3D+0.65%281.3%29^%28x%29
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