Question

SIMPLIFY AND STATE RESRICTIONS?
\[\frac{2x^{2}-5x-3}{2x^{2}-11x+15} \times \frac{4^2-8x-5 }{4x^2+4x+1}\]

Answer 1

Factor every element to get
\[
\frac{2x^{2}-5x-3}{2x^{2}-11x+15} \times \frac{4x^2-8x-5 }{4x^2+4x+1}=\frac{((x-3) (2 x+1)) ((2 x-5) (2
x+1))}{((x-3) (2 x-5)) (2 x+1)^2}
\]
Cancel what you can cancel and state the restrictions

Answer 2

When you cancel you get 1.
Subject to the restrictions that none of the factors are zero.
For example
\[
x\ne 3\\
x\ne -\frac 1 2 \\
etc
\]

Answer 3

OH ! ... my goodness i factored wrong for 2x^2-11x+15...
i put (2x+5)(x+3)
kk

so for restrictions... i would simplify first? then state restrictions?

Answer 4

yes