Question

Hi help in the question - kinematics

Answer 1

@ParthKohli
@rebeccaskell94
@amistre64
@inkyvoyd
@experimentX
@eliassaab
@maheshmeghwal9

Answer 2

with calculus or without calculus??

Answer 3

with or without both will work but full steps please: )

Answer 4

The acceleration is varying so it must have calculus{integration}
but i don't know how to integrate?
may be @experimentX can help:)

Answer 5

\[ \frac{d^2 s}{dt^2 } = f(s)\]

Answer 6

I don't think it should involve this type of differentiation equation ... this is quite complicated

Answer 7

I m giving attachments.
May be of help:)

Answer 8

http://www.wolframalpha.com/input/?i=y%27%27+%3D+2y%5E2%2By%2Cy%280%29%3D0

Answer 9

also, what is the velocity of the particle at rest??

Answer 10

first u must read the attachments to get a clear point of view @mathslover
& after this it is ur wish^_^

Answer 11

If it involves calculus then it should be similar to this question
http://math.stackexchange.com/questions/152575/solving-fracd2dt2-theta-k-sin-theta-for-t

Answer 12

@experimentX can u plz show me what is the integration of a=(2s^2+s)cm/s^2
w.r.t. "s":)

Answer 13

w.r.t.=with respect to

Answer 14

becoz after integration we will put the values of s to get the velocity at any instant:)

Answer 15

I hope this should be of help.

Answer 16

next time add @AravindG :D

Answer 17

k!

Answer 18

from mathslover

Answer 19

Plz help @AravindG : D

Answer 20

?are u mathlover?

Answer 21

no but I also have confusion in this question:/

Answer 22

so asking for help only:)
then urs wish.

Answer 23

before i integrate tell me if we have any info on what s is ? is it diplacement?

Answer 24

or time ?

Answer 25

ya in the question it is given acceleration varies according to displacement
so i think it must be displacement.

Answer 26

then why does the qn say it starts at x=0 ? isnt it s=0?

Answer 27

ya u r right.
Let's wait for mathslover what does he has to say.

Answer 28

@mathslover

Answer 29

here ... x= 0 and s=0 are the same things..