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the lines l and m have vector equations.r=i+j+k+s(i-j+2k) and r=4i+6j+k+t(2i+2j+k) respectively. show that l and m intersect.
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r=(1+s)i+(1-s)j+(1+2s)k r=(4+2t)i+(6+2t)j+(1+t)k Equate both the equations (1+s)i+(1-s)j+(1+2s)k=(4+2t)i+(6+2t)j+(1+t)k nw equating the coefficients since i,j,k are linearly independent 1+s=4+2t-(1) 1-s=6+2t-(2) 1+2s=1+t-(3) solve (1) and (2) to get the value of s and t. then apply the values of s and t in (3) and see if they satisfy the equation. If they satisfy then l and m intersect. See if u can do.
can u do?
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