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Rationalizing the denominator: is it possible to do this one in 1 step? \[1 \over 1 + \sqrt{3} - \sqrt {5}\]
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I did this: \[\frac{1}{1 + \sqrt{3} - \sqrt{5}} \times \frac{-1+\sqrt{3}-\sqrt{5}}{-1 + \sqrt{3}- \sqrt{5}} = \frac{-1+\sqrt{3}-\sqrt{5}}{7-2\sqrt{15}}\] Is there a simpler way?
@jackellyn @ajprincess help please!
It looks fine to me, i'm not sure any other way. Sorry.
ya I too am nt sure of any other way..sorry.
let \[a=\sqrt{3}-\sqrt{5}\] \[1/(1+a)\] \[1/(1+a)*(1-a)/(1-a)\] \[(1-a)/(1-a ^{2})\]
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or \[1/(1+\sqrt{3}-\sqrt{5})*(1+\sqrt{3}+\sqrt{5})/(1+\sqrt{3}+\sqrt{5})\]
thanks!
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