Question

STOP AND HELP PLZ!
Assuming x ≠ 0 and y ≠ 0, what is the quotient of 8x^(9y³+2x^(6y²+8x³))/4y³?
Which equation represents the line passing through the points (1, 4) and (-2, 13)?
x - 3y = 7
3x - y = 7
x + 3y = 7
3x + y = 7
PLZ JUST HELP!

Answer 1

\(\huge \frac{8x^{(9y^3+2x^{(6y^2+8x^3)})}}{4y^3}\)

Answer 2

Like this?

Answer 3

Yes

Answer 4

plz help

Answer 5

Power of a power, this is an exponent rule;

\(\huge \frac{8x^{(9y^3+2x^{(6y^2+8x^3)})}}{4y^3}\) would now become \(\huge \frac{8x^{(9y^3+2x)*(6y^2+8x^3)}}{4y^3}\)

Answer 6

\(\huge \frac{8x^{(9y^3+2x)*(6y^2+8x^3)}}{4y^3}\) Disassociate 8.
\(\huge \frac{8*x^{(9y^3+2x)*(6y^2+8x^3)}}{4y^3}\) Simplify
\(\huge \frac{2x^{(9y^3+2x)*(6y^2+8x^3)}}{y^3}\) We can also disassociate 2/y^3
\(\huge \frac{2}{y^3} *x^{(9y^3+2x)*(6y^2+8x^3)}\) Now multiply the stuffs in the exponent thing.

Answer 7

okay

Answer 8

I got \(\huge \frac{2}{y^3}*x^{2y^2(27y^3+6x+36y^2+8y)}\) through simplifying.

Answer 9

@saifoo.khan

Answer 10

okay what about the other one?